Statement $$(P \Rightarrow Q) \wedge (R \Rightarrow Q)$$ is logically equivalent to

We need to simplify $$(P \Rightarrow Q) \wedge (R \Rightarrow Q)$$.

Using the equivalence $$P \Rightarrow Q \equiv \neg P \vee Q$$:

$$ (P \Rightarrow Q) \wedge (R \Rightarrow Q) = (\neg P \vee Q) \wedge (\neg R \vee Q) $$

By the distributive law (factoring out $$Q$$):

$$ = Q \vee (\neg P \wedge \neg R) $$

By De Morgan's law: $$\neg P \wedge \neg R = \neg(P \vee R)$$

$$ = Q \vee \neg(P \vee R) = \neg(P \vee R) \vee Q $$

This is the implication form:

$$ = (P \vee R) \Rightarrow Q $$

The correct answer is $$(P \vee R) \Rightarrow Q$$.