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A committee of 3 experts is to be selected out of a panel of 7 persons. Three ofΒ them are engineers, Three are managers and, one is both engineer and manager.Β In how many ways can the committee be selected if it must have atleast oneΒ engineer and one manager?
Number of ways the committee be selected with atleast oneΒ engineer and one manager,
= $$3_{C_{1}}3_{C_{1}}3_{C_{1}} +Β 3_{C_{1}}3_{C_{2}} + 3_{C_{2}}3_{C_{1}} +Β 3_{C_{2}}1_{C_{1}} + 3_{C_{2}}1_{C_{1}}$$
= 9 + 9 + 9 + 3 + 3 = 33
Hence, option A is the correct answer.
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