The compound statement $$(\sim(P \wedge Q)) \vee ((\sim P) \wedge Q) \Rightarrow ((\sim P) \wedge (\sim Q))$$ is equivalent to

A

$$((\sim P) \vee Q) \wedge ((\sim Q) \vee P)$$

B

$$(\sim Q) \vee P$$

C

$$((\sim P) \vee Q) \wedge (\sim Q)$$

D

$$(\sim P) \vee Q$$