Let $$(1 + x + 2x^2)^{20} = a_0 + a_1 x + a_2 x^2 + \ldots + a_{40} x^{40}$$, then $$a_1 + a_3 + a_5 + \ldots + a_{37}$$ is equal to:

A

$$2^{20}(2^{20} - 21)$$

B

$$2^{19}(2^{20} - 21)$$

C

$$2^{19}(2^{20} + 21)$$

D

$$2^{20}(2^{20} + 21)$$