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In how many ways a committee of 5 members be selected from 7 men and 5 ladies, consisting of 3 men and 2 ladies?
The number of ways to select a committee of 5 members consisting 3 men and 2 women are,
Selecting 3 men out of the 7 men in $$^7C_3\ =\ 35$$ ways
Selecting 2 women out of the 5 women in $$^5C_2\ =\ 10$$ ways
Total number of ways = 35 * 10 = 350 ways.
Hence, the correct answer is option D.
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