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If $$(\log_3 x)(\log_x 2x)(\log_{2x} y) = \log_x x^2$$, then y equals
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Simplifying the expression: $$\ \frac{\ \log\ x}{\log\ 3}\times\ \ \frac{\ \log\ 2x}{\log\ x}\times\ \ \frac{\ \log\ y}{\log\ 2x}$$, which is $$\ \log_3y$$
Now, the RHS of the equation is equal to 2.Â
Hence, $$\ \log_3y$$ = 2, or y isÂ
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