Solution
Simplifying the expression: $$\ \frac{\ \log\ x}{\log\ 3}\times\ \ \frac{\ \log\ 2x}{\log\ x}\times\ \ \frac{\ \log\ y}{\log\ 2x}$$, which is $$\ \log_3y$$
Now, the RHS of the equation is equal to 2.
Hence, $$\ \log_3y$$ = 2, or y is
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Simplifying the expression: $$\ \frac{\ \log\ x}{\log\ 3}\times\ \ \frac{\ \log\ 2x}{\log\ x}\times\ \ \frac{\ \log\ y}{\log\ 2x}$$, which is $$\ \log_3y$$
Now, the RHS of the equation is equal to 2.
Hence, $$\ \log_3y$$ = 2, or y is
