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If $$2^x = 64 and 4^y = 256$$,then find the value of $$\left(\frac{1}{x}\right) + \left(\frac{1}{y}\right)$$.
$$\frac{2}{5}$$
$$\frac{5}{12}$$
$$\frac{2}{3}$$
$$\frac{7}{12}$$
$$ 2^6=64 $$
$$ 4^4=256 $$
thus x=6, y=4
$$\frac{1}{6} +\frac{1}{4} $$
solving we get $$ \frac{5}{12} $$
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