The area of an equilateral triangular park is equal to $$5\sqrt{3}$$ times the area of a triangular field with sides 18 m, 80 m and 82 m. What is the side of the triangular park?
Given sides of the triangle are 18,80 and 82 cm
these are the sides of a right angled triangle as 9,40,41 is a Pythagorean triplet
So area of a right angled triangle=(1/2)bh
=(1/2)*80*18
=720 sq cm
Given area a equilateral triangle=$$5\sqrt{3}$$*720
$$\sqrt{3}a^{2}/4$$=$$5\sqrt{3}$$*720
$$a^{2}$$=36*100*4
a=6*10*2
a=120 cm
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