In a circle with center C and radius $$6\sqrt{2}$$ cm, PQ and SR are two parallel chords separated by one of the diameters. If $$\angle QC=45^{circ}$$, and the ratio of the perpendicular distance of PQ and SR from C is 3: 2, then the area, in sq. cm, of the quadrilateral PQRS is

A

$$4(3+\sqrt{14})$$

B

$$4(3\sqrt{2}+\sqrt{7})$$

C

$$20(3+\sqrt{14})$$

D

$$20(3\sqrt{2}+\sqrt{7})$$