Sign in
Please select an account to continue using cracku.in
↓ →
An article manufactured by a company consists of two parts: Part I and Part II. In the process of manufacturing of Part I, 9 products out of 100 are likely to be defective. Similarly, 5 products out of 100 are likely to be defective in the manufacture of Part II. What is the probability that the final assembled article will NOT be defective?
Probability to be defective for part I = $$\dfrac{9}{100}$$
Probability to be defective for part II =Β $$\dfrac{5}{100}$$
Final assembled problem will not be defective if bothΒ Part I and Part II are not defective.
Probability =Β $$\dfrac{91}{100}\times\ \dfrac{95}{100}$$ = 0.8645
Answer is option B.
Was this solution helpful?
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation