The length of one side of a rhombus is 13 cm and one of the diagonals is 10 cm. What is the length of the other diagonal?
Diagonals of a rombus bisect eachother at 90°
One side rhombus = 13 cm
length of one diagonal = 10 cm
We will apply here Pythagoras Theorem
(h²) = (b²) + (p²)
on putting the values in the equation and then solving it we get,
13² = b² + 5²
169 = b² + 25
b² = 169 -25
b² = 144
(Take Square root on both sides)
b= 12
As perpendicular(p)= 12cm
therefore diagonal = 2 p= 2$$\times$$12 = 24 cm
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