Question 62

The value of $$\frac{36 \div 42 of 6 \times 7 + 24 \times 6 \div 18 + 3 \div (2 - 6) - (4 + 3 \times 2) \div 8}{21 \div 3 of 7}$$ is:

Solution

$$\frac{36 \div 42 of 6 \times 7 + 24 \times 6 \div 18 + 3 \div (2 - 6) - (4 + 3 \times 2) \div 8}{21 \div 3 of 7}$$

= $$\frac{36 \div 252 \times 7 + 24 \times 6 \div 18 + 3 \div (2 - 6) - (4 + 3 \times 2) \div 8}{21 \div 21}$$

= $$36 \div 252 \times 7 + 24 \times 6 \div 18 + 3 \div (-4) - (10) \div 8$$

= $$36 \times \frac{1}{252} \times 7 + 24 \times 6 \times \frac{1}{18} - 3 \times \frac{1}{4} - (10) \times \frac{1}{8}$$

= $$1 + 8 - \frac{3}{4} - \frac{5}{4}$$

= 1 + 8 - 2 = 7

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