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Question 62
15% of an alloy was silver. If in a quantity of alloy there was 51 g of silver, what was the quantity of the other elements in the alloy?
Solution
Given that
Let total quantity of alloy was x
15% of an alloy was silver. i.e=51g
other element quantity in alloy was 85%
$$15\%x=51$$
$$\frac{15\times(x)}{100}=51$$
$$(x)=\frac{5100}{15}$$
$$x=340$$
other element quantity in alloy was 85% so calculate 85% of 340
$$85\% of 340=340\times\frac{85}{100}$$
$$=3.4\times{85}$$
$$=289$$
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