Question 60
Which formula gives the refractive index of second medium with respect to the first?
Solution
Snell's law
$$n_{1}$$sin(i) = $$n_{1}$$sin(r)
$$\frac{n_{1}}{n_{2}}$$ = $$\frac{sin(i)}{sin(r)}$$
refractive index = $$\frac{sin(i)}{sin(r)}$$
$$n_{1}$$ and $$n_{2}$$ are refractive indices of the corresponding medium
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