Question 60

Which formula gives the refractive index of second medium with respect to the first?

Solution

Snell's law

$$n_{1}$$sin(i) = $$n_{1}$$sin(r)

$$\frac{n_{1}}{n_{2}}$$ = $$\frac{sin(i)}{sin(r)}$$

refractive index = $$\frac{sin(i)}{sin(r)}$$

$$n_{1}$$ and $$n_{2}$$ are refractive indices of the corresponding medium

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