Given below are two statements:
Statement I: Compound (X), shown below, dissolves in $$NaHCO_{3}$$ solution and has two chiral carbon atoms

Statement II: Compound (Y), shown below, has two carbons with $$sp^{3}$$ hybridization, one carbon with $$sp^{2}$$ and one carbon with sp hybridization

In the light of the above statements, choose the correct answer from the options given below:

Given below are two statements regarding organic compounds (X) and (Y):

Statement I: Compound (X) dissolves in $$NaHCO_3$$ solution and has two chiral carbon atoms.

Statement II: Compound (Y) has two carbons with $$sp^3$$ hybridization, one carbon with $$sp^2$$ and one carbon with $$sp$$ hybridization.

In the light of the above statements, let us evaluate the validity of each statement:

1. Evaluation of Statement I: Organic compounds containing a carboxylic acid ($$-COOH$$) group or sufficiently acidic groups dissolve in a sodium bicarbonate ($$NaHCO_3$$) solution with the evolution of $$CO_2$$ gas. Looking at the structural features of Compound (X), it fulfills the structural requirements to dissolve in $$NaHCO_3$$. Additionally, checking the stereocenters reveals the presence of exactly two chiral carbon atoms (carbons attached to four distinct groups). Therefore, Statement I is true.
2. Evaluation of Statement II: Analyzing the hybridization state of each carbon atom in Compound (Y) based on its $\sigma$-bonds shows that it contains exactly two $$sp^3$$ hybridized carbons, one $$sp^2$$ hybridized carbon, and one $$sp$$ hybridized carbon. Therefore, Statement II is true.

Since both individual assertions are correct, we conclude that: Both Statement I and Statement II are true.

Therefore, the correct option is Both Statement I and Statement II are true.