Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
An electric bulb rated $$60\text{ W}$$ at $$220\text{ V}$$. If the bulb is used on $$110\text{ V}$$ supply, its power would be
The resistance stays the same, so $$P = \frac{V^2}{R}$$ is proportional to $$V^2$$. Halving the voltage makes the power $$\frac{1}{4} \times 60 = 15\text{ W}$$.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.