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Question 6

A projectile can have the same range $$R$$ for two angles of projection. If $$T_1$$ and $$T_2$$ be the time of flights in the two cases, then the product of the two time of flights is directly proportional to

Solution

Solution & Explanation

1. Understand Complementary Angles for Same Range

A projectile launched with an initial velocity $$u$$ achieves the exact same horizontal range ($$R$$) at two distinct projection angles that are complementary to each other. Let these two angles be:

  • First angle: $$\theta_1 = \theta$$
  • Second angle: $$\theta_2 = 90^\circ - \theta$$

The standard formula for horizontal range ($$R$$) under gravitational acceleration ($$g$$) is:

$$R = \frac{u^2 \cdot \sin(2\theta)}{g} = \frac{2 \cdot u^2 \cdot \sin\theta \cdot \cos\theta}{g}$$


2. Set Up Time of Flight Equations

The total time of flight ($$T$$) for a projectile is given by the formula $$T = \frac{2 \cdot u \cdot \sin\alpha}{g}$$. We write down the specific time of flight expressions for both individual trajectories:

  • For the first case ($$\theta_1 = \theta$$):

    $$T_1 = \frac{2 \cdot u \cdot \sin\theta}{g}$$

  • For the second case ($$\theta_2 = 90^\circ - \theta$$):

    $$T_2 = \frac{2 \cdot u \cdot \sin(90^\circ - \theta)}{g} = \frac{2 \cdot u \cdot \cos\theta}{g}$$


3. Multiply the Time of Flights

Now, let us calculate the product of the two times of flight ($$T_1 \cdot T_2$$):

$$T_1 \cdot T_2 = \left( \frac{2 \cdot u \cdot \sin\theta}{g} \right) \cdot \left( \frac{2 \cdot u \cdot \cos\theta}{g} \right)$$

$$T_1 \cdot T_2 = \frac{2}{g} \cdot \left( \frac{2 \cdot u^2 \cdot \sin\theta \cdot \cos\theta}{g} \right)$$


4. Identify the Proportionality

Notice that the grouped term inside the parentheses is the exact mathematical expression for the horizontal range ($$R$$) established in Step 1:

$$T_1 \cdot T_2 = \frac{2}{g} \cdot R$$

Since the factor $$\frac{2}{g}$$ is completely constant, we drop it to express the final scaling relationship:

$$T_1 \cdot T_2 \propto R$$

Concept Check: The product of the flight times directly tracks the horizontal range because one time profile captures the vertical component scaled by $$\sin\theta$$ and the other captures the horizontal configuration scaled by $$\cos\theta$$. Combined, their product tracks the cross-multiplied parameter $$\sin\theta \cdot \cos\theta$$, which defines horizontal displacement capacity.


Correct Option Key: Option C ($$R$$)

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