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An open vessel at $$27^\circ\text{C}$$ is heated until two fifth of the air (assumed as an ideal gas) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is
The vessel is open, so pressure stays atmospheric, and the volume is constant, so $$n_1T_1 = n_2T_2$$. Two fifth of the air escapes, so $$n_2 = \frac{3}{5}n_1$$. Hence $$T_2 = \frac{5}{3} \times 300 = 500\text{ K}$$.
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