Question 59
A man lifts a luggage of 25 kg from the ground and puts it on the head, 2.5 m above the ground. If the value of g = 10 ms$$^{-2}$$, then the value of work done by him on the luggage is:
Solution
M = 15kg
g = 10m/s^2
h = 2.5m
As work done by an object is equal to the potential energy stored in an object.
Therefore,
W = mgh
= $$25\times 10\times 2.5$$
= 625J.
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