In $$\triangle ABC, D$$ and E are points on AB and BC, respectively, such that DE is parallel to AC. If DE = 3 cm, AC = 5 cm and the area of trapezium ACED = 32 cm$$^2$$, then what will be the area of $$\triangle BDE$$?

A

$$\frac{144}{17} cm^2$$

B

$$\frac{48}{5} cm^2$$

C

$$16 cm^2$$

D

$$18 cm^2$$