Among following compounds, the number of those present in copper matte is ______
A. CuCO$$_3$$
B. Cu$$_2$$S
C. Cu$$_2$$O
D. FeO

Explanation

During the extraction of copper from copper pyrites, the roasted ore is mixed with silica and smelted in a reverberatory furnace.

During smelting, iron oxide reacts with silica to form iron silicate slag.

$$FeO+SiO_2\rightarrow FeSiO_3$$

The slag is removed, while copper is obtained in the form of copper matte.

According to NCERT, copper matte consists of

$$Cu_2S \text{ and } FeS$$

Now, evaluating the given compounds:

$$CuCO_3$$ is a carbonate ore of copper and is not a constituent of copper matte.

Therefore,

$$CuCO_3$$

is not present.

$$Cu_2S$$ is one of the principal constituents of copper matte.

Therefore,

$$Cu_2S$$

is present.

$$Cu_2O$$ is formed later during the conversion process when part of $$Cu_2S$$ is oxidized. It is not a constituent of the initial copper matte.

Therefore,

$$Cu_2O$$

is not present.

$$FeO$$ is produced during roasting but reacts with silica to form iron silicate slag and is removed from the furnace.

$$FeO+SiO_2\rightarrow FeSiO_3$$

Therefore,

$$FeO$$

is not present in copper matte.

Hence, among the given compounds, only

$$Cu_2S$$

is present in copper matte.

Therefore, the total number of compounds present is

$$1$$

Hence, the correct answer is

$$1$$