The major product Y in the following reaction is:

Step 1: Formation of Compound X (Haloform Reaction)

The starting material is acetophenone.

1. Reagent: It is treated with sodium hypochlorite, which acts as a source of Cl2 and NaOH in situ, followed by acidic workup 
2. Reaction Type: This is a classic haloform reaction targeting the methyl ketone functional group.
3. Outcome: The methyl group ($\text{-CH}_3$) is converted into chloroform , while the carbonyl group is oxidized to a carboxylate salt. Upon acidification ($\text{H}^+$), it yields benzoic acid.

Compound X: Benzoic acid ($\text{Ph-COOH}$)

Step 2: Conversion of X to an Acyl Chloride

1. Reagent: Benzoic acid is treated with thionyl chloride SOCl2
2. Reaction Type: Nucleophilic acyl substitution.
3. Outcome: The hydroxyl group of the carboxylic acid is substituted by a chlorine atom -Cl, releasing SO2 and HCl as gaseous by-products.

Intermediate: Benzoyl chloride-

Step 3: Formation of Compound Y (Amidation)

1. Reagent: The benzoyl chloride intermediate is reacted with aniline Ph-NH2
2. Reaction Type: Nucleophilic acyl substitution / Schotten-Baumann reaction.
3. Outcome: The lone pair on the nitrogen atom of aniline attacks the electrophilic carbonyl carbon of benzoyl chloride, kicking off the chloride leaving group ($\text{Cl}^-$). This forms a stable secondary amide linkage.

Compound Y: N-phenylbenzamide / Benzanilide