Question 57

A cylindrical vessel of radius 30 cm and height 42 cm is full of water. Its contents are emptied into a rectangular tub of length 75 cm and breadth 44 cm. The height (in cm) to which the water rises in the tub is: (Take $$\pi = \frac{22}{7}$$)

Solution

Volume of the cylindrical vessel = $$\pi r^2 h = \frac{22}{7} \times 30^2 \times 42$$

= 118800

If we replace the water from the cylindrical vessel to rectangular tub then volume should be equal of the cylindrical vessel rectangular tub.

Volume of the cylindrical vessel = Volume of rectangular tub

118800 = length $$\times breadth \times height$$

118800 = 75 $$\times 44 \times height$$

Height = 118800/3300 = 36 cm


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