Three years ago, the population of a town was 1 lakh. If the annual increase during three successive years was at the rate of 4%, 2% & 2% per annum respectively, find the approximate present population.
Three years back population = 1 lakh
Present population = $$100000\times\ \frac{104}{100}\times\ \frac{102}{100}\times\ \frac{102}{100}$$ = 104*102*10.2 = 108201.6 $$\approx\ $$ 108202
Answer is option C.
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