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Question 56
If $$\frac{x}{y} + \frac{y}{x} = 2, (x, y \neq 0)$$, then the value of $$(x - y)$$ is:
Solution
$$\frac{x}{y}+\frac{y}{x}=2$$
$$\frac{x^2+y^2}{xy}=2$$
$$x^2+y^2=2xy$$
$$x^2+y^2-2xy=0$$
$$\left(x-y\right)^2=0$$
$$x-y=0$$
Hence, the correct answer is Option B
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