Question 56

Below question contains two equations as I and II. You have to solve both equations and determine the relationship between them and choose correct option:

I. $$2x^{2} + 3x - 35 = 0$$
II. $$4y^{2} + 10y - 104 = 0$$

Solution

$$2x^{2} + 3x - 35 = 0$$

This can be written as

$$2x^2+10x-7x-35=0$$

$$2x\left(x+5\right)-7\left(x+5\right)=0$$

$$\left(2x-7\right)\left(x+5\right)=0$$

Thus, x = 7/2 or -5

Similarly, for $$4y^{2} + 10y - 104 = 0$$

This can be written as

$$4y^2-16y+26y-104=0$$

$$4y\left(y-4\right)+26\left(y-4\right)=0$$

y = 4 or -26/4

Therefore, x and y are unequal, and no relation can be established between them.

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