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Question 56

5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0.1 M solution? Given: Molar Mass of Na, O and H is 23, 16 and 1 g mol$$^{-1}$$ respectively

Correct Answer: 180

Solution

Stock: 5g NaOH (MW=40) = 0.125 mol in 450 mL. M = 0.125/0.45 = 0.2778 M.

For 500 mL of 0.1 M: moles = 0.05. V = 0.05/0.2778 = 0.180 L = 180 mL.

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