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The standard deviation of the set {10, 11, 12, 9, 8} is
1.6
$$\surd 2$$
2
$$2\surd 2$$
Standard deviation =$$\sqrt{\ \frac{\Sigma\ \left(x-y\right)^2}{N-1}}=\sqrt{\ \frac{10}{4}}=\frac{\sqrt{\ 10}}{2}=1.58$$ ~ 1.6
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