If y (x) satisfies the differential equation y'- ytan x = 2x sec x and y(0) = 0, then

A

$$y\left(\frac{\pi}{4}\right) = \frac{\pi^2}{8\sqrt{2}}$$

B

$$y' \left(\frac{\pi}{4}\right) = \frac{\pi^2}{18}$$

C

$$y\left(\frac{\pi}{3}\right) = \frac{\pi^2}{9}$$

D

$$y' \left(\frac{\pi}{3}\right) = \frac{4 \pi}{3} + \frac{2 \pi^2}{3\sqrt{3}}$$