Question 54

The compound interest on a sum of ₹ 24500 at 10% p.a for $$2\frac{2}{5}$$ years interest compounded yearly is:

Solution

Principal sum $$P$$ = Rs. 24,500

Rate of interest = $$r=10\%$$ and time period = $$t=2\frac{2}{5}$$ years

Amount when compounded annually (time in fraction) = $$P\times(1+\frac{r}{100})^t\times(1+\frac{\frac{2}{5}r}{100})$$     {$$\because$$ time in mixed fraction is $$\frac{2}{5}$$}

= $$24,500\times(1+\frac{10}{100})^2\times(1+\frac{2\times10}{500})$$

= $$24,500\times(\frac{121}{100})\times(\frac{26}{25})$$

= $$49\times121\times\frac{26}{5}=30830.80$$

$$\therefore$$ Compound interest = $$30830.8-24500=6330.80$$

=> Ans - (C)


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