In the following questions two equations numbered I and II are given. You have to solve both the equations and
Give answer a: if x > y
Give answer b: if x ≥ Y
Give answer c: if x < y
Give answer d: if x ≤ Y
Give answer e: if x = y or the relationship between x and y cannot be established.
I. $$x^{2}-7x+10=0$$
II. $$y^{2} -5y+6=0$$
I.$$x^{2} - 7x + 10 = 0$$
=> $$x^2 - 2x - 5x + 10 = 0$$
=> $$x (x - 2) - 5 (x - 2) = 0$$
=> $$(x - 2) (x - 5) = 0$$
=> $$x = 5 , 2$$
II.$$y^{2} - 5y + 6 = 0$$
=> $$y^2 - 2y - 3y + 6 = 0$$
=> $$y (y - 2) - 3 (y - 2) = 0$$
=> $$(y - 2) (y - 3) = 0$$
=> $$y = 2 , 3$$
$$\therefore$$ No relation can be established.
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