In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
a: If x > y
b: If x < y
c: If x ≥ y
d: If x ≤ y
e: If x = y or the relationship cannot be established
I. $$4x^{2} - 17x + 18 = 0$$
II. $$2y^{2} - 21y + 40 = 0$$
Root of quadratic equation $$(ax^{2} + bx + c =0)$$ = $$\frac{-b \pm \sqrt{b^2 -4ac}}{2a}$$
For equation I : a=4, b = -17 and c= 18
On solving the quadratic equation I we get x = (18/8) or (2)
For equation II : a=2 , b = -21 and c= 40
On solving the quadratic equation I we get y = (8) or (10/4)
It is clear that x<y
Option B is correct answer.
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