Question 54

A liquid is heated to a temperature of $$50^\circ\text{F}$$ (Fahrenheit) and the temperature of another liquid was raised to $$25^\circ\text{C}$$ (Celcius). The difference in temperature of the two liquids in degree celcius is

Using $$C = \frac{5}{9}(F - 32)$$, we get $$\frac{5}{9} \times (50 - 32) = 10^\circ\text{C}$$. The difference between the two liquids is $$25^\circ\text{C} - 10^\circ\text{C} = 15^\circ\text{C}$$.

Was this solution helpful?

Get AI Help

50,000+ JEE Students Trusted Our Score Calculator

Predict your JEE Main percentile, rank & performance in seconds

Ask AI