Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
The resistance of hot tungsten filament is about $$10$$ times the cold resistance. What will be the resistance of $$100$$ W and $$200$$ V lamp when not in use?
The resistance of the lamp when it is in use (hot resistance) can be calculated using the power formula:
$$P = \frac{V^2}{R_{hot}}$$
Rearranging the formula to solve for $$R_{hot}$$:
$$R_{hot} = \frac{V^2}{P}$$
Substituting the given values:
$$R_{hot} = \frac{(200)^2}{100}$$
$$R_{hot} = \frac{40000}{100}$$
$$R_{hot} = 400 \ \Omega$$
According to the problem, the resistance of the hot tungsten filament is about 10 times its cold resistance (the resistance when not in use). This gives us the relation:
$$R_{hot} = 10 \times R_{cold}$$
Therefore, the cold resistance $$R_{cold}$$ is:
$$R_{cold} = \frac{R_{hot}}{10}$$
$$R_{cold} = \frac{400}{10}$$
$$R_{cold} = 40 \ \Omega$$
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation