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Iodine reacts with concentrated $$\text{HNO}_3$$ to yield Y along with other products. The oxidation state of iodine in Y, is
Concentrated nitric acid oxidises iodine to iodic acid, $$\text{I}_2 + 10\text{HNO}_3 \rightarrow 2\text{HIO}_3 + 10\text{NO}_2 + 4\text{H}_2\text{O}$$. In $$\text{HIO}_3$$, $$1 + x - 6 = 0$$, so the oxidation state of iodine is $$+5$$.
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