In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
a: If x > y
b: If x < y
c: If x ≥ y
d: If x ≤ y
e: If x = y or the relationship cannot be established
I. $$x^{2} - 11x + 30 = 0$$
II. $$2y^{2} - 9y + 10 =0$$
Root of quadratic equation $$(ax^2 + bx + c =0) = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$$
For equation I : a=1 , b = -11 and c= 30
On solving the quadratic equation I we get x = (5) or (6)
For equation II : a=2 , b = -9 and c= 10
On solving the quadratic equation II we get y = (2.5) or (2)
It is clear that y<x.
Option A is correct answer.
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