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A straight line L through the point (3, -2) is inclined at an angle $$60^\circ$$ to the line $$\sqrt{3} x + y = 1$$. If L also intersects the x-axis, then the equation of L is
$$y + \sqrt{3} x + 2 - 3 \sqrt{3} = 0$$
$$y - \sqrt{3} x + 2 + 3 \sqrt{3} = 0$$
$$\sqrt{3} y - x + 3 + 2 \sqrt{3} = 0$$
$$\sqrt{3} y + x - 3 + 2 \sqrt{3} = 0$$
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