Question 51

Two trains of equal length are running on parallel lines in the same direction at 46 km/h and 36 km/h. The faster train passes, the slower train in 36 sec. The length of each train is :

Solution

Let length of each train = $$x$$ m

Speed of the trains = 46 km/hr and 36 km/hr

Since, the trains are moving in same direction, => Relative speed = 46 - 36 = 10 km/hr

= $$10 \times \frac{5}{18} = \frac{25}{9}$$ m/s

Time taken = 36 sec

$$\therefore \frac{x + x}{\frac{25}{9}} = 36$$

=> $$2x = 36 \times \frac{25}{9}$$

=> $$2x = 4 \times 25 = 100$$

=> $$x = \frac{100}{2} = 50$$ m

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