Question 51

The Area of a rectangle is $$27m^2$$ and its length is 3 times of its breadth. The perimeter of the rectangle is:

Solution

Length of rectangle be l and breadth be b

$$ l=3b and l \times b = 27 cm^2 $$

So, we get $$3b \times b = 27$$

=> $$3b^2 = 27$$

=>$$ b^2 = 9$$

Solving these we get $$ l = 9 and b = 3,$$

Perimeter $$ = 2(9+3) = 24 cm $$

Option A is correct.

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