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In the following sequence, if the first half of the alphabets are written in reverse order, then which is the $$9^{\text{th}}$$ letter from the right?<br>(Left) E P M Z N R B C K F G H T N (Right)
There are 14 letters, so the first half is E P M Z N R B, which reversed becomes B R N Z M P E. The new sequence is B R N Z M P E C K F G H T N. Counting from the right, N, T, H, G, F, K, C, E, P, the 9th letter is P.
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