Solution
$$x^{2} —4x+4=0 $$
$$x^{2} —2x - 2x+4=0 $$
$$x(x — 2) - 2(x — 2)=0 $$
$$(x — 2)(x — 2)=0 $$
x = 2
now,
16$$(x^{4}-\frac{1}{x^{4}})$$
= 16$$(2^{4}-\frac{1}{2^{4}})$$
= 16$$(16-\frac{1}{16})$$
= $$16^2 - 1$$ = 255
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