How many grams of residue is obtained by heating 2.76 g of silver carbonate? (Given: Molar mass of C, O and Ag are 12, 16 and 108 g mol$$^{-1}$$ respectively)

Silver Carbonate decomposes into Silver $$(Ag)$$ on heating:

$$Ag_2CO_3\longrightarrow\ 2Ag+CO_2+\frac{1}{2}O_2$$

The obtained residue is Silver ($$Ag$$).

Molar Mass of $$Ag_{2}CO_3$$:

$$2\left(108\right)+12+3\left(16\right)=276gmol^{-1}$$

From Reaction,

$$276g\ \ Ag_2CO_3\longrightarrow\ 216g\ Ag\ $$

therefore,

$$2.76g\ Ag_2CO_3\longrightarrow\ \frac{216}{276}\times\ 2.76=2.16g$$

Therefore, Option B is correct $$i.e$$ $$2.16g$$