Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.
A. $$n = 3, l = 2, m = +1$$
B. $$n = 4, l = 0, m = 0$$
C. $$n = 6, l = 1, m = 0$$
D. $$n = 5, l = 1, m = +1$$
E. $$n = 2, l = 1, m = +1$$
Choose the correct answer from the options given below:

For multi-electron atoms, the energy of an atomic orbital is determined using Bohr-Bury's $$n+l$$ rule:

Let's Calculate each separately:

A. $$n=3,\ l=2\ \left(3d\ orbital\right)\longrightarrow\ n+l=3+2=5$$

B. $$n=4,\ l=0\ \left(4s\ orbital\right)\longrightarrow\ n+l=4+0=4$$

C. $$n=6,\ l=1\ \left(6p\ orbital\right)\longrightarrow\ n+l=6+1=7$$

D. $$n=5,\ l=1\ \left(5p\ orbital\right)\longrightarrow\ n+l=5+1=6$$

E. $$n=2,\ l=1\ \left(2p\ orbital\right)\longrightarrow\ n+l=2+1=3$$

Therefore, by rules:

$$E<B<A<D<C$$

Therefore, Option D is correct.