Which of the following is the correct structure of L-Glucose? (Four Fischer projection structures shown)

The Fischer projection of an aldo-hexose is drawn with the aldehyde group $$CHO$$ at the top (C-1) and the terminal primary alcohol $$CH_2OH$$ at the bottom (C-6).

For any carbohydrate, the D/L notation is decided solely by the configuration at the penultimate carbon (the chiral carbon farthest from the carbonyl group, C-5 in an aldo-hexose).

Rule:
 • $$\;OH$$ on the right at C-5 → D-sugar.
 • $$\;OH$$ on the left at C-5 → L-sugar.

Glucose contains four stereogenic centres (C-2, C-3, C-4, C-5). The Fischer projection of D-glucose is

CHO
 |
 H—C—OH (C-2, OH right)
 OH—C—H (C-3, OH left)
 H—C—OH (C-4, OH right)
 H—C—OH (C-5, OH right) ← D-indicator
 |
CH2OH

The L-enantiomer is the mirror image at every chiral centre, so its pattern must be:

CHO
 |
 OH—C—H (C-2, OH left)
 H—C—OH (C-3, OH right)
 OH—C—H (C-4, OH left)
 OH—C—H (C-5, OH left) ← L-indicator
 |
CH2OH

Among the four given Fischer projections, only Option A shows:

• $$OH$$ on the left at C-5 (confirming the L-series), and
• the remaining $$OH$$ groups arranged left-right-left up the chain (C-4 to C-2) exactly as required for the mirror image of D-glucose.

Therefore, the correct structure of L-glucose is provided in Option A.

Final Answer: Option A which is: (Fischer projection of L-glucose).