$$20\text{ g}$$ of ice is dropped in to a calorimeter of water equivalent $$10\text{ g}$$ containing $$90\text{ g}$$ of water at $$40^\circ\text{C}$$. The resultant temperature of the mixture is (specific heat of water $$= 1\text{ cal g}^{-1}\,^\circ\text{C}^{-1}$$, Latent heat of ice $$= 80\text{ cal g}^{-1}$$)

A

$$0^\circ\text{C}$$

B

$$20^\circ\text{C}$$

C

$$10^\circ\text{C}$$

D

$$30^\circ\text{C}$$