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$$\sqrt{144} + \sqrt[3]{216} = \sqrt{a} = 6\sqrt{b}$$ then $$\frac{a}{4b}$$ is equal to ______
Correct Answer: 9
$$\sqrt{144} + \sqrt[3]{216} = 12 + 6 = 18$$. So $$\sqrt{a} = 18$$ gives $$a = 324$$, and $$6\sqrt{b} = 18$$ gives $$b = 9$$. Then $$\frac{a}{4b} = \frac{324}{36} = 9$$.
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