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Question 5

Saket takes the number 2021. There are two 2s, one 0 and one 1. Using these numbers, he makes 3-digit numbers, the sum of all these numbers is

Solution

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Using the digits $$2,2,0,1$$ to form valid three-digit numbers gives $$220,202,210,201,120,102,212,221,122$$. Their sum is $$1610$$. Hence the required sum is $$1610$$.

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