Question 49

A bag contains 4 five rupee coins, 3 two rupee coins and 3 one rupee coins. If 6 coins are drawn from the bag at random, what are the odds in favour of the draw yielding maximum amount?

Solution

Total number of coins in the bag = 4 + 3 + 3 = 10

If 6 coins are drawn from the bag at random, then the probability that the draw yields maximum amount is given by,

= $$\frac{4_{C_{4}} \times 3_{C_{2}}}{10_{C_{6}}}$$

= $$\frac{1 \times 3}{210}$$

= $$\frac{1}{70}$$

Odds in favour of the draw = $$1 - \frac{1}{70} = \frac{69}{70}$$

Hence, option C is the correct answer.

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