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A bag contains 4 five rupee coins, 3 two rupee coins and 3 one rupee coins. If 6Β coins are drawn from the bag at random, what are the odds in favour of the drawΒ yielding maximum amount?
Total number of coins in the bag = 4Β + 3 + 3 = 10
If 6Β coins are drawn from the bag at random, then the probability that the draw yields maximum amount is given by,
= $$\frac{4_{C_{4}} \times 3_{C_{2}}}{10_{C_{6}}}$$
= $$\frac{1 \times 3}{210}$$
= $$\frac{1}{70}$$
Odds in favour of the draw = $$1 -Β \frac{1}{70} = \frac{69}{70}$$
Hence, option CΒ is the correct answer.
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