Question 48

Shyam had three note books X, Y and Z. Of these, X had 120 pages, Y had 10% more and Z had 10% less. If he tore out 5%, 10% and 15% of pages in X, Y and Z respectively, then what percent of total pages did he tear out?

Solution

Total number of books shyam had,

X = 120, Y = (1.1 x 120) = 132, Z = (0.9 x 120) = 108

Total number of books he tore,

X = 5 % of X = (0.05 x 120) = 6

Y = 10% of Y = (0.1 X 132) = 13.2

Z = 15% of Z = (0.15 x 108) = 16.2

Percentage of books he tore,

$$\Rightarrow \frac{6 + 13.2 + 16.2}{120 + 132 + 108}$$ x 100

$$\Rightarrow \frac{35.4}{360}$$ x 100 = 9.83%

Hence, option D is the correct answer.

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