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Let $$f(x)=\frac{1-x(1+\mid1-x\mid)}{\mid1-x\mid}Cos(\frac{1}{1-x})$$ for $$x\neq1$$. Then
$$\lim_{x\rightarrow1^{-}}f(x)=0$$
$$\lim_{x\rightarrow1^{-}}f(x)$$ does not exist
$$\lim_{x\rightarrow1^{+}}f(x)=0$$
$$\lim_{x\rightarrow1^{+}}f(x)$$ does not exist
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